8p^2-80p+192=0

Solution for 8p^2-80p+192=0 equation:

8p^2-80p+192=0

a = 8; b = -80; c = +192;
Δ = b2-4ac
Δ = -802-4·8·192
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-16}{2*8}=\frac{64}{16}
=4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+16}{2*8}=\frac{96}{16}
=6
$